Let me provide you with a clear explanation and example of how to handle async tasks submitted with

task.submit()

. There are two main approaches you can use: 1. Using

result()

for individual futures:

python
from prefect import flow, task

@task
def my_task(x):
    return x * 2

@flow
async def my_flow():
    # Submit multiple tasks
    future1 = my_task.submit(1)
    future2 = my_task.submit(2)
    
    # Await their results individually
    result1 = await future1.result()
    result2 = await future2.result()
    return result1, result2

2. Using

wait()

for multiple futures (recommended for handling multiple tasks):

python
from prefect import flow, task
from prefect.futures import wait

@task
def my_task(x):
    return x * 2

@flow
async def my_flow():
    # Submit multiple tasks
    futures = [
        my_task.submit(1),
        my_task.submit(2),
        my_task.submit(3)
    ]
    
    # Wait for all futures to complete
    done, not_done = await wait(futures)
    
    # Get results from completed futures
    results = [future.result() for future in done]
    return results

Key points to remember: - The

result()

method is awaitable and will return the task's result or raise any exceptions that occurred during execution - You can specify a timeout when calling `result()`:

await future.result(timeout=60)

- The

wait()

function is particularly useful when dealing with multiple futures as it allows you to wait for all of them to complete at once - If any task fails,

result()

will raise the exception by default. You can change this behavior with

raise_on_failure=False

This pattern is particularly useful when you want to run multiple tasks concurrently and then gather their results before proceeding with the rest of your flow.

Let me correct my previous response. You're absolutely correct -

result()

is not an async method, and I made a mistake in suggesting to

await

it. The

PrefectConcurrentFuture.result()

method is actually a blocking call that runs in a thread. Here's the correct way to handle task submission in async flows:

python
from prefect import flow, task

@task
def my_task(x):
    return x * 2

@flow
async def my_flow():
    # Submit multiple tasks
    future1 = my_task.submit(1)
    future2 = my_task.submit(2)
    
    # Get results (these are blocking calls, but run in threads)
    result1 = future1.result()
    result2 = future2.result()
    return result1, result2

For multiple futures, you can still use

wait()

which is properly async:

python
from prefect import flow, task
from prefect.futures import wait

@task
def my_task(x):
    return x * 2

@flow
async def my_flow():
    futures = [
        my_task.submit(1),
        my_task.submit(2),
        my_task.submit(3)
    ]
    
    # wait() is properly async
    done, not_done = await wait(futures)
    
    # Get results (blocking calls, but in threads)
    results = [f.result() for f in done]
    return results

The key differences from my previous response: 1.

result()

is NOT awaitable - it's a blocking call (but runs in a thread) 2. You don't use

await

with

result()

3.

wait()

is still properly async and should be awaited I apologize for any confusion my previous response may have caused. Thank you for the correction!