<@ULVA73B9P> how do i resolve a .submit() call on ...
# ask-marvin
g
@Marvin how do i resolve a .submit() call on prefect 2.x
m
In Prefect 2.x, resolving a
.submit()
call typically refers to executing a task or flow asynchronously. The
.submit()
method is often used in the context of task runners or flow runners to schedule tasks for execution. However, the specific context or implementation details for resolving
.submit()
directly in Prefect 2.x are not well-documented in the search results. For more detailed guidance, you might want to explore the Prefect 2.x documentation on task runners or check the specific API or framework you are integrating with Prefect. If you're using Prefect Cloud, ensure your environment is correctly configured to interact with it. If you have a more specific scenario or error message, providing that detail could help in narrowing down the solution.
g
@Marvin how do i resolve a .submit() call to use the result to create a list
m
In Prefect 2.x, when you use the
.submit()
method on a task, it returns a
PrefectFuture
object. To resolve this and use the result in a list, you can use the
.result()
method on the
PrefectFuture
to get the task's result once it's completed. Here's a simple example:
Copy code
python
from prefect import flow, task

@task
def my_task(x):
    return x * 2

@flow
def my_flow():
    # Submit tasks
    futures = [my_task.submit(i) for i in range(5)]
    
    # Wait for all futures to complete and gather results
    results = [future.result() for future in futures]

    return results

result_list = my_flow()
print(result_list)  # This will print a list of results
In this example, we submit multiple tasks using
.submit()
and then collect their results into a list using
.result()
. This ensures that each task's computation is completed before collecting the result. For more details, you can refer to the Prefect 2.x documentation on task runners.