<@ULVA73B9P>, how do I pass arbitrary arguments to...
# ask-marvin
v
@Marvin, how do I pass arbitrary arguments to an on_failure hook? I want to pass the same arguments received by the flow
m
To pass arbitrary arguments to an
on_failure
hook in Prefect 3.x, you need to define the hook function in such a way that it can accept the necessary arguments. The hook itself can be a function that takes parameters and you can pass the flow's arguments to it. Here's a basic outline of how you might set this up: 1. Define your hook function: Ensure your function can accept the arguments you want to pass.
Copy code
python
def my_failure_hook(flow_args, **kwargs):
    # Perform some actions using flow_args
    print("Flow failed with arguments:", flow_args)
2. Attach the hook to your flow: When defining your flow, you can specify the
on_failure
hook and pass the necessary arguments.
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python
from prefect import flow

@flow(on_failure=[lambda state, flow_args: my_failure_hook(flow_args)])
def my_flow(arg1, arg2):
    # Flow logic here
    pass
In this setup,
my_failure_hook
will be called with the arguments
arg1
and
arg2
when the flow fails. You can replace
flow_args
with the specific arguments you want to pass. For more details on hooks and state management in Prefect, you can refer to the Prefect documentation on managing states.