Please help me to clear up my confusion on instantiating prefect flows. I have three dbt commands to run:

dbt deps
dbt snapshot
dbt run

For now I'm running them by reusing the instance of DbtShellTask:

dbt_task = DbtShellTask(name="Running dbt commands", ...)

dbt_clean_task_invoke   = dbt_task("dbt deps")
dbt_deps_task_invoke    = dbt_task("dbt snapshot")
dbt_run_task_invoke     = dbt_task("dbt run")

With having this setup, my schematic will have three boxes(tasks) with name

Running dbt commands

which is difficult to identify which is which. In order to fix that, do I have to instantiate for each command like below.

dbt_clean_task = DbtShellTask(name="Running dbt deps command", ...)
dbt_deps_task  = DbtShellTask(name="Running dbt snapshot command", ...)
dbt_run_task   = DbtShellTask(name="Running dbt run command", ...)

dbt_clean_task_invoke   = dbt_clean_task("dbt deps")
dbt_deps_task_invoke    = dbt_deps_task("dbt snapshot")
dbt_run_task_invoke     = dbt_run_task("dbt run")

Hey @Sumit Kumar Rai, I think this is right. If you want it a bit shorter, maybe you can do

dbt = DbtShellTask

with Flow("a") as flow:
    dbt_clean_task = dbt(name="Running dbt deps command", ...)("dbt deps")
    dbt_deps_task  = dbt(name="Running dbt snapshot command", ...)("dbt snapshot")
    dbt_run_task   = dbt(name="Running dbt run command", ...)("dbt run")

You could also do:

dbt = DbtShellTask(**kwargs)
with Flow("a") as flow:
    dbt_deps = dbt(command="dbt deps", task_args={"name" = "Running dbt deps command"}
    dbt_snapshot = dbt(command="dbt snapshot", task_args={"name": "Running dbt snapshot command"}, upstream_task=[dbt_deps])
...

Thank you @Kevin Kho and @Matthias Roels for the reply. I followed as @Matthias Roels’s response as it is more readable for me. And the solution worked.