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Hello!
I was wondering how to get the flow result location inside a task? Is this possible to do?

<@U02EGHD4V4N> you can get the result location after you ran the task, e.g.:
```from prefect import task, Flow
from prefect.engine.results import LocalResult


@task(result=LocalResult(location="sample_result.prefect"))
def hello_world():
    return "Hello world"


with Flow("local-results") as flow:
    hello_world()


state = flow.run()
hello_world = flow.get_tasks()[0]
print(hello_world.result.location)```


The question was unclear. So what I want to do is to inside a task upload some data to a S3 bucket, but i want this bucket to be the same as the flows result bucket.

```@task()
def hello_world():
    
    infered_bucket = here i want the        flow bucket
    return "Hello world"

with Flow("local-results") as flow:
    hello_world()


flow.result = S3Result(bucket="some_bucket")```

<@U02EGHD4V4N> I think the easiest way would be to reuse a global variable name and use boto3 inside of your task:
```import boto3
from prefect.engine.results import S3Result

bucket = "some_bucket"

@task
def upload_object(file_name):
    s3_client = boto3.client('s3')
    s3_client.upload_file(file_name, bucket, f"path/on/s3/{file_name}")


with Flow("local-results") as flow:
    upload_object()


flow.result = S3Result(bucket=bucket)```