Hey, I know you can set a task or flow run name using a string variable. But is it possible to do within a dict? like this:

@task(task_run_name="reset-indy-config-{device['name']}")

or is it only possible to do

{device}

?

You can use an f-string:

@task(task_run_name=f"reset-indy-config-{device['name']}")

ooh thank you was missing that!! appreciate it

just to note, an f-string is often not what you want here, because an f-string is rendered immediately (with whatever the value of

foo

is at function definition time) as opposed to a template string (without the f) which is rendered after the task is called, and therefore can be named according to the params it received

In [1]: from prefect import task

In [2]: foo = dict(x=42)

In [3]: @task
   ...: def t(foo: dict): pass

In [4]: t.with_options(task_run_name=f"{foo['x']}")(dict(x=43))
15:48:32.451 | INFO    | Task run '42' - Created task run '42' for task 't'
15:48:32.460 | INFO    | Task run '42' - Finished in state Completed()

In [5]: t.with_options(task_run_name="{foo[x]}")(dict(x=43))
15:48:43.996 | INFO    | Task run '43' - Created task run '43' for task 't'
15:48:44.001 | INFO    | Task run '43' - Finished in state Completed()

the way i'm calling my tasks is immediately appending them to an array as i use .submit on them. so would it be t.with_options(blah).submit()?

you don't need to use

with_options

if you don't need to template it differently each time, I just did because I wanted to show the examples side by side with the same underlying task object if you're always going to template the same way, you'd be free to do this

@task(task_run_name="reset-indy-config-{device[name]}")

oh wow it really was a matter of removing the quotes lol