<@ULVA73B9P> is it possible to wrap and existing f...
# marvin-in-the-wild
p
@Marvin is it possible to wrap and existing function into a flow and serve it immediately? I do not want to make any changes to
my_function
. I tried the following but running the flow I'm getting errors that my_function is not a flow.
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def serve_flow():
    import prefect
    prefect.flow(my_function).serve()
m
Ah, the classic dilemma of trying to fit a square peg into a round hole without using a hammer. You want to wrap an existing function into a Prefect flow and serve it immediately, but alas,
my_function
is not magically becoming a flow. How tragic. First things first, let's get the version of Prefect you're using. Which version of Prefect are you on?
p
@Marvin 2
m
It seems you need to turn your existing function into a Prefect flow using the
@flow
decorator. Here's the distilled wisdom from the docs: 1. Wrap your function with the
@flow
decorator:
This magically transforms your function into a Prefect flow. 2. Serve the transformed flow: Only after this transformation can you serve the flow. Here's how you can drizzle some syntax sugar on your code, while keeping
my_function
unchanged:
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python
from prefect import flow

@flow
def serve_flow():
    my_function()

serve_flow.serve(name="my-deployment")
Your function
my_function
remains untouched, and the
serve_flow
is now a Prefect flow that can be served. For more info, you can explore these links: - Flows in Prefect - Using Prefect Client If this doesn't quench your thirst for knowledge, feel free to complain some more.
p
@Marvin this does not address my question, I have a function
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def my_function(x=1):
    print(x)
at some different place in the code I want to wrap it into a flow with prefect.flow(my_function) and serve it. If I do it like this, the function seems to not be properly annotated as a flow during runtime and the flow run fails.
m
Oh, I see. You want to knight
my_function
into a Prefect flow without actually touching it. Quite ambitious. Let's see if Prefect 2.0 allows you to dynamically wrap an existing function into a flow and serve it, as you desire, without being too fussy about its origins. I'll delve deeper into the realm of Prefect 2.0 documentation and possibly GitHub issues to fetch your salvation. Please hold on. Here’s the reality wrenched out from the depths of Prefect documentation and GitHub issues: 1. Dynamic Wrapping: It appears Prefect 2.0 emphasizes statically wrapping functions with the
@flow
decorator, ensuring flows are properly tracked and served. The approach you tried doesn’t directly align with Prefect's intended usage, hence the failure. 2. Serving Flows: Prefect indeed allows you to dynamically create deployments and serve flows. However, these flows must be properly defined and annotated using static constructs. ### Solution Given these constraints, the closest workaround while keeping
my_function
untouched is to use a wrapper flow function to serve it: Ensure
my_function
is available in the scope, then wrap it within the flow like this:
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python
from prefect import flow

def my_function(x=1):
    print(x)

@flow
def wrapper_flow(x=1):
    return my_function(x)

if __name__ == "__main__":
    wrapper_flow.serve(name="my_deployment")
This ensures that the function is considered a flow at runtime, allowing you to serve it seamlessly. ### References - Prefect Flows Concept - Serving Flows If you really want dynamic functionality at runtime, you might need to explore advanced techniques or even custom integrations, but that’s another labyrinth. Would you like me to dive deeper into potential custom solutions, or does this satiate your quest?
p
@Marvin can I do it without explicitly copying the entire call signature (all the arguments)?
m
Oh, the drudgery of copying arguments. I understand your pain. Fortunately, Python's introspection capabilities can help us avoid this tedium. You can dynamically wrap the function while preserving its signature. Here's how you can do it using
functools.wraps
and `inspect.signature`:
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python
from prefect import flow
import inspect
from functools import wraps

def my_function(x=1):
    print(x)

def wrap_with_flow(func):
    @wraps(func)
    @flow
    def wrapped_func(*args, **kwargs):
        return func(*args, **kwargs)
    return wrapped_func

# Dynamically wrap the existing function
my_function_flow = wrap_with_flow(my_function)

if __name__ == "__main__":
    my_function_flow.serve(name="my_deployment")
This keeps
my_function
untouched and dynamically wraps it in a flow without explicitly copying its call signature. The
wraps
decorator ensures that the wrapped function retains the metadata of the original function, including its signature. To make sure this works correctly: 1. Import the necessary modules. 2. Define your existing function
my_function
. 3. Create a
wrap_with_flow
function that adds the
@flow
decorator dynamically. 4. Use this helper to wrap
my_function
. And voilà,
my_function
is now a dynamical flow. Here’s your dynamic magic potion. If you want to read more about Prefect flows and dynamic wrapping, glance through: - Prefect Flows Concept - Python's `functools.wraps` If this still leaves you yearning for a different approach, do let me know.
c
@Paweł Biernat what errors are you seeing? that pattern works just fine for me and is equivalent to a decorator approach
p
@Chris White I'm getting
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prefect.exceptions.MissingFlowError: Function with name 'my_flow' is not a flow. Make sure that it is decorated with '@flow'.
The code is basically
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def my_flow(x: int):
    print(x)


def serve_flow():
    import prefect

    prefect.flow(my_flow).serve()
and is run via the poetry endpoint
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serve_flow_test = "test:serve_flow"
like so
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poetry run serve_flow_test
I guess that the flow has to be defined in the main scope of the module, instead in a function like what I'm doing. I figured out I need a wrapper in the main scope, kind of like
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@flow
my_flow_wrapper(x: int):
    my_flow(x)
and then I have to serve
my_flow_wrapper
. It's not a great solution, because I have to copy the entire call signature but it works. Can it be done differently?
c
OH! I see the issue: it's with the entrypoint
serve_flow_test = "test:serve_flow"
which doesn't point to a flow object
yea, so you could try defining
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def __getattr__(name: str):
    if name == "serve_flow":
        # prepare your flow here and return it
i'd be curious to know if that works with the entrypoint you had
p
I forgot to mention, that I'm getting the error when at flow run, the serving seems to work just fine
where should I place the
__getattr__
? Directly in the module? Could you post that in the context of the example I prepared?
c
yea so assuming your file was called
test.py
, i'd put it in that file inplace of the
serve_flow
function, and then your entrypoint would be the same (because of the
name == "serve_flow"
check)